9x^2+18+11x=-10x+8

Solution for 9x^2+18+11x=-10x+8 equation:

9x^2+18+11x=-10x+8

We move all terms to the left:

9x^2+18+11x-(-10x+8)=0

We get rid of parentheses

9x^2+11x+10x-8+18=0

We add all the numbers together, and all the variables

9x^2+21x+10=0

a = 9; b = 21; c = +10;
Δ = b2-4ac
Δ = 212-4·9·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*9}=\frac{-30}{18}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*9}=\frac{-12}{18}
=-2/3
$